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LDIF 파일의 항목에서 정보 추출

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LDIF 파일의 항목에서 정보 추출

다음과 같은 항목이 포함된 파일이 있습니다.

ddn: cn=312548,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312548001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312548999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: something else

dn: cn=312544,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312544001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312544999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: after bike

dn: cn=312542,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312542001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312542999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: pen mark

dn: cn=312539,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312539999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
member: cn=312539001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
abcName: used car

dn: cn=312537,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312537001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312537999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: Book bike

dn: cn=312534,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312534999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
member: cn=312534001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=fe7316f7-05d6-439b-8b9b-4364f4936615,ou=Named,ou=Identities,ou=Acti
 ve,ou=Vault,o=abc
abcName: Apple

이제 "Named" 멤버가 포함된 dn 항목만 알고 싶습니다.

출력에는 "abcName" 및 "dn"이 포함되어야 합니다.

답변1

GNU sed 사용

sed 'H;/^$/{h};/abcName/{x;/,ou=Named,/{s/member:[^\n]*\n//g;p}};d' file

dn: cn=312534,ou=Entities,ou=Active,ou=Vault,o=abc
abcName: Apple

답변2

귀하의 샘플에서,

awk -vRS= -F': *|\n' '/,ou=Named,/{print $2, $NF}' < file

출력됩니다:

cn=312534,ou=Entities,ou=Active,ou=Vault,o=abc Apple

( abcName각 항목의 마지막 속성으로 간주되며 ,ou=Named,다른 속성에서 찾을 수 없거나 dn속성 값이 인코딩되지 않습니다.)

ou=NamedLDIF 행 연속( 예: ) 을 고려하려면 ou=Na\n med먼저 제거할 수 있습니다.

awk -vRS= -F': *|\n' '{gsub(/\n /, "")}; /,ou=Named,/{print $2, $NF}' < file

관련 정보