.bashrc에서 반복되는 코드 블록을 사용하는 방법

내 .bashrc에는 100줄의 간단한 코드인 4가지 기능이 있습니다.

함수 이름과 코드의 처음 3줄이 변수라는 점을 제외하면 함수는 동일합니다.

일반적으로 사용되는 97줄의 코드를 추출하여 별도의 인스턴스화 블록에 넣은 다음 4개 함수 각각에서 해당 블록을 호출하려면 어떻게 해야 합니까?

이러한 일반적인 97개 라인을 사용하여 일반 함수 블록을 만들고 아주 작은 함수에서 호출해 보았지만 제대로 작동하지 못했습니다.

상단에 고유한 3줄, 하단에 공통 코드가 있는 함수입니다.

function download_podcaster() 
   
######################################################################
##########                                                  ########## 
#   UNIQUE CODE FOLLOWS  #

#set-up the directory variables

dir_zz="/home/user/podcast_author"  
pone_dir="podcast_author"  
downloads_z="~/Downloads"  

##########   UNIQUE CODE ABOVE                              ##########
##########                                                  ########## 
######################################################################


#  vvvvv COMMON CODE BELOW   vvvvvv


   echo; echo "   .... this output is from youtube-dl ..."; echo

   #download the file
   youtube-dl -f 140 --restrict-filenames -o $dir_zz'/%(title)s.%(ext)s' $1


   #make dir if does not aleready exist
   mkdir -p $dir_zz

   #change to the downloads directory
   cd $dir_zz
   echo
   echo "current dir is:                                   "$(pwd)
   echo
  
   #open the downloads location to show the files with pcmanfm 
   #pcmanfm ~/Downloads &
   pcmanfm $dir_zz &> /dev/null
   
   file_name_z=$(youtube-dl --get-filename --restrict-filenames "$1")
   echo; echo "file name from provided by youtube-dl:            "$file_name_z; echo

   #grab the filename from youtube, and parse it into something useful
   #remove 11 digits before end of file name                
   file_name_z=$(echo $file_name_z | sed 's|...........\.mp4$|.mp4|g' | sed 's|...........\.m4a$|.m4a|g' \
       | sed 's|...........\.webm$|.webm|g' \
       | sed 's|,||g' | sed 's|!||g' | sed 's| |_|g'  |  \
       sed 's|-\.||g' | sed 's|webm||g' | sed 's|mp4||g' | sed 's|\?||g').m4a
           #  remove ,      remove !       replace " " with "_"
           #  remove "-."    remove "webm"
   echo; echo "file name after , ! \" \" ? removed:                "$file_name_z; echo

   var1=$(ls -t | grep -E "^[0-9]{3}" | sort | tail -n  1 | cut --bytes=1-3)
   echo; echo "\$var1 3 digit highest number from file set is:    "$var1; echo
   
   sleep .25
   #create the variable to assign the next file number to front of file name
   next_file_number=$(printf "%03d\n" $((10#$var1+5)))
   echo; echo "File number plus 5 is:                            "$next_file_number; echo

   sleep .25
   #new file name with three digit number in front of filename
   file_name_y=${next_file_number}_${file_name_z}
   echo; echo "concatenated filename is \$file_name_y:            ""$file_name_y"; echo


   #move the old file to the new file name
   mv "$file_name_z" "$file_name_y" 
   echo; echo "                                                  ""$file_name_y"; echo


   #plug phone in. Phone mount point in file system can be seen here
   #echo; cd /var/run/user/$UID/gvfs; ls; echo
   #reference
   #https://askubuntu.com/questions/342319/where-are-mtp-mounted-devices-located-in-the-filesystem
   #
   #How to get to the phone directory on the phone if the directory is dynamically allocated on the 
   #reference  
   #https://askubuntu.com/a/454697/624987
   #phone or changes, use this
   #cd /var/run/user/$UID/gvfs; cd * ; cd *; cd Music; mkdir -p $phone_dir; cd $phone_dir; ls
   #       
   #"cd *" changes to the first directory shown
   
   #grab the directory on the phone in which to place the file
   cd /var/run/user/$UID/gvfs; cd * ; cd *; cd Music; mkdir -p $phone_dir; cd $phone_dir
   phone_dir_long_path=$(pwd)


   echo "  ... now copying the file to the phone -->"; echo
   #copy file to phone
   cp $dir_zz/"$file_name_y" "$phone_dir_long_path"
   echo
   
   #open terminal at directory of files
   gnome-terminal --title="test" --command="bash -c '$phone_dir_long_path; ls; $SHELL'"

   echo
   #open the file name with the default app, usually vlc
   xdg-open $dir_zz/$file_name_y &

   echo
}