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이 코드에서 "eval"이 작동하지 않는 이유는 무엇입니까?

tag-icon • tag-icon variable ffmpeg eval
이 코드에서 "eval"이 작동하지 않는 이유는 무엇입니까?

저해상도 미디어 파일 목록이 포함된 파일을 생성하는 것을 목표로 다음 코드를 작성했습니다.

#!/usr/bin/bash

find "$PWD" -type f -iname "*.avi" -execdir ~/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh {} + >~/pCloudDrive/VisualArts/lowres.films
find "$PWD" -type f -iname "*.mkv" -execdir ~/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh {} + >>~/pCloudDrive/VisualArts/lowres.films
find "$PWD" -type f -iname "*.mp4" -execdir ~/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh {} + >>~/pCloudDrive/VisualArts/lowres.films

보시다시피 위의 코드는 printer.sh다음 코드를 호출합니다.

#!/usr/bin/bash

#The script is meant to print only the results of low resolution, that is starting with 1, 2, 3, 4, 5

if [[ $(ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1) == 2* ]]; then
  echo "$(realpath $1)" && ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1 
elif [[ $(ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1) == 3* ]]; then
  echo "$(realpath $1)" && ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1 
elif [[ $(ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1) == 4* ]]; then
  echo "$(realpath $1)" && ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1 
elif [[ $(ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1) == 5* ]]; then
  echo "$(realpath $1)" && ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1 

fi

코드의 중복을 수정된 변수로 바꾸고 싶습니다 printer.sh.

#!/usr/bin/bash

output=$(ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 $1)
if [[ $($output) == 2* ]]; then
  echo "$(realpath $1)" && eval "$output"
elif [[ $($output) == 3* ]]; then
  echo "$(realpath $1)" && eval "$output"
elif [[ $($output) == 4* ]]; then
  echo "$(realpath $1)" && eval "$output"
elif [[ $($output) == 5* ]]; then
  echo "$(realpath $1)" && eval "$output" 
fi

이제 작동하지 않으며 내가 얻는 출력은 다음과 같습니다.

/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 6: 1920x1024: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 8: 1920x1024: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 10: 1920x1024: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 12: 1920x1024: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 6: 1920x800: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 8: 1920x800: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 10: 1920x800: command not found
/home/jerzy/CS/SoftwareDevelopment/MySoftware/Bash/lowresolution_finder/printer.sh: line 12: 1920x800: command not found

내가 뭘 잘못했나요? 어떻게 다시 작성해야 합니까?

답변1

원하는 내용은 다음과 같습니다.

output=$(ffprobe -v error -select_streams v:0 -show_entries stream=width,height -of csv=s=x:p=0 "$1")
if [[ $output == [2345]* ]]
then 
  echo "$(realpath "$1")" "$output"
fi

eval왜 이것을 사용했는지 모르겠습니다 . eval실행하는 데 사용되는 셸 코드가 포함된 문자열입니다. 출력은 ffprobe코드가 아닙니다.

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