Bash 스크립트: 사용자 입력(읽기)이 제대로 작동하지 않습니다.

파일을 삭제하거나 이름, 내용을 기반으로 프로그램을 닫는 BASH 스크립트를 작성 중입니다. 특히 내용에 따라 파일을 삭제하는 데 문제가 있습니다(사례 2). 내용과 일치하는 모든 파일로 파일을 채울 수 있습니다. 그러나 사용자가 파일 삭제 여부(읽기 사용)를 입력해야 하면 내 코드가 손상됩니다. 이 변수는 사용자 입력을 요청하지 않고 대신 삭제할 파일의 위치를 ​​자동으로 채웁니다.

#!/bin/bash

#set -x
#Programmer: Redacted
#Z: ID: Redacted
#Assignment:  cleaner.sh

directory=`pwd` #sets the directory variable to pwd
string="string"
file="file"
fileFound=matched.txt
possibleFiles=''
result=''
function askDelete #asks for verification
{
    #echo "$fileName was found, still want to delete it? (y/n)"
    read -p "$fileName was found, still want to delete it? (y/n)" continue
    echo "Continue is equal to: $continue"
}


echo    "Welcome to my CLEANER script!"
echo    "Enter 1: delete by filename."
echo    "Enter 2: delete by a string within the file."
echo    "Enter 3 or quit: exit this program."
read command
    case $command in
    "file")
        command=1 ;;
    "string")
        command=2 ;;
    esac

case $command in
    1)
            #Prompts user for which file they want to delete
        echo "What file would you like to delete? "
        read fileName
        #find $PWD -type f -name "$fileName"
        #result= -x $fileName
        if [ -a "$fileName" ]
            then
                askDelete
                if [ $continue == 'y' ] || [ $continue == 'Y' ]
                    then
                        rm $fileName
                        echo "File has been removed"
                    else
                        echo "File has not been removed"
                fi

            else
                echo "No files were found"
        fi

    ;;

    #case where user entered 2
    #user wants to enter a string within the files to delete
    2)
        touch 'matched.txt' #creates the file that will be used
        echo "Enter the string that you wish to have the files containing it to be destroyed"
        read pattern    #user enters what they want to search for
        find $PWD -type f 1>possibleFiles.txt
        #echo $PWD
        #grep -q "$pattern" 'foundFile.txt' 1> matched.txt
        echo 'This is where it breaks'
        cat possibleFiles.txt | while read fileName
        do
            #\echo $fileName
            grep -q "$pattern" "$fileName" 1> matched.txt
            if [ $? == 0 ]
            then
                askDelete
                if [ $continue == 'y' ] || [ $continue == 'Y' ]
                    then
                        rm $fileName
                    else
                        echo  "No found files have been removed"
                fi
            else
                echo "No matches for the pattern were found"
            fi
        done
#
#       if [ $? == 0 ]
#           then
#               askDelete
#               if [ $continue == "Y" ] || [ $continue == "y" ]
#                   then
#                       #cat matched.txt 
#                       for file in 'matched.txt'
#                       do
    #                       echo 'bleh'
#                       done
    #               else
#                       echo  "No found files have been removed"
#               fi
#           else
#               echo "No matches for the pattern were found"
#       fi
#       fi
        ;;

    #case where user entered 3
    #user wants to exit
    3)
        echo "Goodbye friend"
        exit
    ;;

    *)
        echo Digit 1, 2 or 3 must be entered
esac

나는 문제가 프로그램 상단 근처의 AskDelete 함수 내부 어딘가에 있다고 생각합니다. 구체적으로 다음 줄은 다음과 같습니다. read -p "$fileName을 찾았지만 여전히 삭제하시겠습니까? (y/n)" continue

도움을 주시면 감사하겠습니다.